Ip Addressing And Subnetting Workbook Version 2.0 Student Answers Official

| | CIDR | Subnet Mask | Network ID | Hosts usable | |-------------|----------|----------------|----------------|------------------| | LAN A | /25 | 255.255.255.128 | 192.168.10.0 | 126 | | LAN B | /26 | 255.255.255.192 | 192.168.10.128 | 62 | | LAN C | /27 | 255.255.255.224 | 192.168.10.192 | 30 | | WAN link | /30 | 255.255.255.252 | 192.168.10.224 | 2 |

: Class A (1–126), B (128–191), C (192–223). D/E ignored here. Part 2 – Subnetting a Class C Address (192.168.1.0/24) Problem : Create 4 subnets with at least 25 hosts each. | | CIDR | Subnet Mask | Network

Below is Alex’s with explanations written in the margins. Part 1 – Address Classification & Default Masks | IP Address | Class | Default Subnet Mask | Network ID | Host ID | |-----------------------|-----------|-------------------------|----------------|--------------| | 10.250.1.15 | A | 255.0.0.0 | 10.0.0.0 | 250.1.15 | | 172.31.200.99 | B | 255.255.0.0 | 172.31.0.0 | 200.99 | | 192.168.5.10 | C | 255.255.255.0 | 192.168.5.0 | 10 | | 203.0.113.88 | C | 255.255.255.0 | 203.0.113.0 | 88 | | 8.8.8.8 | A | 255.0.0.0 | 8.0.0.0 | 8.8.8 | Below is Alex’s with explanations written in the margins

: Large contiguous block from 10.0.22.0/24 onward. Epilogue Alex submits the workbook. The instructor’s note on top says: “Version 2.0 completed correctly. Next step: practice until you can do each problem in under 45 seconds.” The instructor’s note on top says: “Version 2