Principles Of Physics A Calculus-based Text 5th Edition Solution May 2026

So, the magnitude of the resultant displacement is 48.2 km, and its direction is 38.3° south of west.

:

θ = tan^(-1)(-30.3 km / 37.5 km) = -38.3° So, the magnitude of the resultant displacement is 48

R = √(37.5 km)^2 + (-30.3 km)^2 = 48.2 km

Using Newton's second law:

Let's break down the displacement into its north and west components:

The acceleration of the block is 4.90 m/s^2. So, the magnitude of the resultant displacement is 48

a = F / m = (mg * sin(30.0°)) / m = g * sin(30.0°) = 9.80 m/s^2 * 0.500 = 4.90 m/s^2