But the actual grid can vary. The key insight: .
turn_left() for i in range(2): deliver_package() move() move() turn_right() move() turn_left() move() turn_around() move() turn_right() move() move() turn_left()
But Level 48 specifically wants to avoid repeating move() calls inside the loop when the distance between houses is constant. From the official solution archives and community answers, the most common correct solution for Rapid Router Level 48 (Python) is: rapid router level 48 solution
deliver_package()
def deliver_one(): move() turn_left() move() deliver() turn_around() move() turn_left() turn_left() for i in range(2): deliver_one() for j in range(2): move() turn_right() move() turn_left() move() turn_around() move() turn_right() for j in range(2): move() turn_left() deliver_one() But the actual grid can vary
# Rapid Router Level 48 Solution def deliver_package(): move() turn_left() move() deliver() turn_around() move() turn_left()
W = Warehouse (start) H = House (delivery point) # = Wall / obstacle . = Road Row 0: W . . H # . . H Row 1: . . # . . . . . Row 2: H . . . . # . H From the official solution archives and community answers,
Wait – that’s still long. But the that passes the level’s efficiency check is:
